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break in List?

I have code something like this:

departmentList.Foreach

(department =>

{

employeeList.ForEach

(employee=>

{

if (department.Pid.Equals(employee.Pid))

{

var employeeInfo = new EmployeeInfo

{

DeptName = employee.DeptName,

FullName = employee.FullName

};

employeeInfoList.Add(employeeInfo);

found = true;

break; ----------------------> Unresolved jump

}

);

}

);

I want to exit through loop once employeeInfo is added in employeeInfoList. But when i add 'break;' , i get this error message 'Unresolved jump'

Does anyone know why?

creativity..

sanjeev40084 Monday, August 31, 2009 3:19 PM

The following is in the help system:

The following rules apply to variable scope in lambda expressions:

A variable that is captured will not be garbage-collected until the delegate that references it goes out of scope.
Variables introduced within a lambda expression are not visible in the outer method.
A lambda expression cannot directly capture a ref or out parameter from an enclosing method.
A return statement in a lambda expression does not cause the enclosing method to return.
A lambda expression cannot contain a goto statement, break statement, or continue statement whose target is outside the body or in the body of a contained anonymous function.

Here is the link:

http://msdn.microsoft.com/en-us/library/bb397687.aspx

If you really need this type break to occur, you should consider changing from the ForEach extension method to a standard for/each statement.

Hope this helps.

www.insteptech.com ; msmvps.com/blogs/deborahk
We are volunteers and ask only that if we are able to help you, that you mark our reply as your answer. THANKS!

Marked As Answer bysanjeev40084 Monday, August 31, 2009 3:29 PM

DeborahK Monday, August 31, 2009 3:26 PM

The following is in the help system:

The following rules apply to variable scope in lambda expressions:

A variable that is captured will not be garbage-collected until the delegate that references it goes out of scope.
Variables introduced within a lambda expression are not visible in the outer method.
A lambda expression cannot directly capture a ref or out parameter from an enclosing method.
A return statement in a lambda expression does not cause the enclosing method to return.
A lambda expression cannot contain a goto statement, break statement, or continue statement whose target is outside the body or in the body of a contained anonymous function.

www.insteptech.com ; msmvps.com/blogs/deborahk
We are volunteers and ask only that if we are able to help you, that you mark our reply as your answer. THANKS!

Marked As Answer bysanjeev40084 Monday, August 31, 2009 3:29 PM

DeborahK Monday, August 31, 2009 3:26 PM

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