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Random picture in picturebox

Hi there,

I need some help with this.

When I click on a button shall 4pictures randomly appear in 4 pictureboxes.
I need to create a method for this but I have no idea how I'm supposed to do. The pictures that I use is from the resources folder.

I hope someone can help me.

John

john8555 Sunday, October 18, 2009 8:23 AM

Hi,

Here is a sample code. Hope it helps.

        private void button1_Click(object sender, EventArgs e)
        {
            List<string> pictureNames = new List<string>();
            pictureNames.Add("_1000002314_1");
            pictureNames.Add("_1000002314_2");
            pictureNames.Add("_1000002315_1");
            pictureNames.Add("a");

            List<PictureBox> pictureBoxex = new List<PictureBox>();
            pictureBoxex.Add(pictureBox1);
            pictureBoxex.Add(pictureBox2);
            pictureBoxex.Add(pictureBox3);
            pictureBoxex.Add(pictureBox4);

            ResourceManager rm = WindowsFormsApplication1.Properties.Resources.ResourceManager;
            for (int i = 0; i < pictureBoxex.Count; i++)
            {
                
                int randomPictureIndex=new Random().Next(0,pictureNames.Count);
                string randomPictureName = pictureNames[randomPictureIndex];
                pictureNames.Remove(randomPictureName);
                Image img = rm.GetObject(randomPictureName) as Image;
                pictureBoxex[i].Image = img;
            }
        }

Proposed As Answer byTamer OzMVPMonday, October 19, 2009 7:40 AM
Marked As Answer byYiChun ChenMSFT, ModeratorMonday, October 19, 2009 11:28 AM

Tamer Oz Sunday, October 18, 2009 9:21 AM

Hi,

Here is a sample code. Hope it helps.

        private void button1_Click(object sender, EventArgs e)
        {
            List<string> pictureNames = new List<string>();
            pictureNames.Add("_1000002314_1");
            pictureNames.Add("_1000002314_2");
            pictureNames.Add("_1000002315_1");
            pictureNames.Add("a");

            List<PictureBox> pictureBoxex = new List<PictureBox>();
            pictureBoxex.Add(pictureBox1);
            pictureBoxex.Add(pictureBox2);
            pictureBoxex.Add(pictureBox3);
            pictureBoxex.Add(pictureBox4);

            ResourceManager rm = WindowsFormsApplication1.Properties.Resources.ResourceManager;
            for (int i = 0; i < pictureBoxex.Count; i++)
            {
                
                int randomPictureIndex=new Random().Next(0,pictureNames.Count);
                string randomPictureName = pictureNames[randomPictureIndex];
                pictureNames.Remove(randomPictureName);
                Image img = rm.GetObject(randomPictureName) as Image;
                pictureBoxex[i].Image = img;
            }
        }

Proposed As Answer byTamer OzMVPMonday, October 19, 2009 7:40 AM
Marked As Answer byYiChun ChenMSFT, ModeratorMonday, October 19, 2009 11:28 AM

Tamer Oz Sunday, October 18, 2009 9:21 AM

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